Mathematics

Definite Integral. Applications

Calculation of the definite integral and its applications: fundamental theorem of calculus, calculation of areas of planar regions, and volumes of revolution.

Definite integral: Given a function f(x)f(x) and an interval [a,b][a, b], the definite integral is equal to the area bounded by the graph of f(x)f(x), the x-axis, and the vertical lines x=ax=a and x=bx=b.
A=abf(x)dxA = \int_a^b f(x) dx
Area under a curve

Fundamental Theorem of Calculus (Barrow's Rule): The definite integral of a continuous function f(x)f(x) on a closed interval [a,b][a, b] is equal to the difference between the values of an antiderivative F(x)F(x) at the endpoints of the interval.
abf(x)dx=F(b)F(a)\int_a^b f(x) dx = F(b) - F(a)

Properties of the definite integral
  • The value of the definite integral changes sign if the limits of integration are swapped.
    abf(x)dx=baf(x)dx\displaystyle \int_a^b f(x) dx = -\int_b^a f(x) dx
  • When the limits of integration are the same, the integral is zero.
    aaf(x)dx=0\displaystyle \int_a^a f(x) dx = 0
  • If cc is an interior point of the interval [a,b][a, b], the integral can be split into the sum of two integrals over the intervals [a,c][a, c] and [c,b][c, b].
    abf(x)dx=acf(x)dx+cbf(x)dx\displaystyle \int_a^b f(x) dx = \int_a^c f(x) dx + \int_c^b f(x) dx

Mean Value Theorem for Definite Integrals
If a function f(x)f(x) is continuous on an interval [a,b][a, b], then there exists a point c[a,b]c \in [a, b] such that:
abf(x)dx=f(c)(ba)\int_a^b f(x) dx = f(c) \cdot (b-a)
Mean Value Theorem for Definite Integrals
Case 1. Area under a curve
A=abf(x)dxA = \left| \int_a^b f(x) dx \right|
Case 1. Area under a curve

Case 2. Area under a curve
The curve intersects the x-axis at c.
A=acf(x)dx+cbf(x)dxA = \left| \int_a^c f(x) dx \right| + \left| \int_c^b f(x) dx \right|
Case 2. Area under a curve with intersection on x-axis

Case 3. Area between 2 curves
A=ab[f(x)g(x)]dxA = \left| \int_a^b [f(x) - g(x)] dx \right|
Case 3. Area between 2 curves

Case 4. Area between 2 intersecting curves
A=ab(f(x)g(x))dx+bc(f(x)g(x))dxA = \left| \int_a^b (f(x) - g(x)) dx \right| + \left| \int_b^c (f(x) - g(x)) dx \right|
Case 4. Area between 2 intersecting curves
Volumes of revolution:
A volume of revolution is obtained by rotating an arc of the function f(x)f(x) around the x-axis. The volume of the generated shape is calculated as:
V=πab[f(x)]2dxV = \pi \int_a^b [f(x)]^2 dx
Volume of revolution
Calculation of arc length
L=ab1+[f(x)]2dxL = \int_a^b \sqrt{1+[f'(x)]^2} dx

Area of a surface of revolution
A=ab2πf(x)1+[f(x)]2dxA = \int_a^b 2\pi f(x) \sqrt{1+[f'(x)]^2} dx

Work done by a force
W=abF(x)dxW = \int_a^b F(x) dx